Air Resistance would be:
RA = - (rCdA(v)^2)/2
Where A is the surface area of the bullet and Cd the coefficient drag, r the density of air and v the speed, v^2 the speed square.
or RA = - (r x Cd x (Pi x r^2) x V^2)/2
Area of circular bullet = Pi x r^2
So if we increase velocity 5 times then RA will be increased by 25 times.
And if we decrease radius 5 times then RA will be decreased by 25 times.
KS-19 (Sair) round is 100 mm in diameter and 50 mm in radius.
While "23 mm High Altitude Recoilless Multi Stage Gun" round is 23 mm in diameter and 11.5 mm in radius.
KS-19 (Sair) altitude is 12,700 m.
11.5 mm (radius) round is 5 times less than 50 mm (radius) round.
So if round velocity is increased 5 times and radius of round is decreased 5 times we have
no overall change in Air Resistance.
Then 23 mm KS-19 (Sair) round is not slowed by Air Resistance as increase in velocity is off set
by decrease in round radius. Or more specifically round's radius is decreased 5 times to decrease round's
Area 25 times.
So instead of KS-19 altitude of 12,700 meters, 23 mm round can reach latitude of 20,000 meters.
Assuming of course it is "23 mm High Altitude Recoilless Multi Stage Gun" design.
jfb, you have forgot about decrease in round radius that off sets increase in velocity.